Chemical measurements
Whenever a measurement is made in chemistry, there is always some uncertaintyThe interval within which the true value of a quantity can be expected to lie. in the result obtained. There are many causes of uncertainty in chemical measurements. For example it may be difficult to judge:
- whether a thermometer is showing a temperature of 24.0掳C, 24.5掳C or 25.0掳C
- exactly when a chemical reaction has finished
There are two ways of estimating uncertainty:
- by considering the resolutionFor a measuring instrument, the smallest change in a quantity that gives a change in the reading that can be seen. of measuring instruments
- from the rangeA measure of spread found by subtracting the smallest number from the biggest number. In other words, the difference between the highest and lowest values in a set of data. of a set of repeat measurements
Estimating uncertainty from measuring instruments
The resolution of a measuring instrument is the smallest change in a quantity that gives a change in the reading that can be seen. A thermometer with a mark at every 1.0掳C has a resolution of 1.0掳C. It has a higher resolution than a thermometer with a mark at every 2.0掳C.
The uncertainty of a measuring instrument is estimated as plus or minus (卤) half the smallest scale division. For a thermometer with a mark at every 1.0掳C, the uncertainty is 卤 0.5掳C. This means that if a student reads a value from this thermometer as 24.0掳C, they could give the result as 24.0掳C 卤 0.5掳C.
For a digitalInformation stored as discrete values usually represented as numbers. This contrasts with analogue data which is represented by continuous data, usually in waves. measuring instrument, the uncertainty is half the last digit shown on its display. For a timer reading to 0.1 s, the uncertainty is 卤 0.05 s.
Estimating uncertainty from sets of repeat measurements
For a set of repeat measurements, the uncertainty is 卤 half the range. This means that the value can be given as the mean value 卤 half the range.
Worked example
Question
The table shows five measurements for the volume of acid required in a neutralisation reaction.
Calculate the mean volume and estimate the uncertainty.
Test number | 1 | 2 | 3 | 4 | 5 |
Volume | 24.0 | 24.5 | 23.5 | 25.0 | 23.0 |
Test number |
---|
1 |
2 |
3 |
4 |
5 |
Volume |
---|
24.0 |
24.5 |
23.5 |
25.0 |
23.0 |
mean = \(\frac{24.0+24.5+23.5+25.0+23.0}{5}\)
= 24.0 cm3
range = (biggest value - smallest value)
= 25.0 - 23.0
= 2.0 cm3
uncertainty = 卤 half the range
= \(\frac{2.0}{2}\) cm3
= 卤 1.0 cm3
So the volume is 24.0 cm3 卤 1.0 cm3.
Showing uncertainty on a graph
Uncertainty can also be shown on a graph. All the repeat readings for each value of the independent variable are plotted. Vertical lines joining these values represent the uncertainty.