Prescribed practical 9 - the strength of an electromagnet (2)
Results
Current in A | Reading 1 (no. of paperclips) | Reading 2 (no. of paperclips) | Average (no. of paperclips) |
0 | |||
0.1 | |||
0.2 | |||
0.3 | |||
0.4 | |||
0.5 | |||
0.6 |
Current in A | 0 |
---|---|
Reading 1 (no. of paperclips) | |
Reading 2 (no. of paperclips) | |
Average (no. of paperclips) |
Current in A | 0.1 |
---|---|
Reading 1 (no. of paperclips) | |
Reading 2 (no. of paperclips) | |
Average (no. of paperclips) |
Current in A | 0.2 |
---|---|
Reading 1 (no. of paperclips) | |
Reading 2 (no. of paperclips) | |
Average (no. of paperclips) |
Current in A | 0.3 |
---|---|
Reading 1 (no. of paperclips) | |
Reading 2 (no. of paperclips) | |
Average (no. of paperclips) |
Current in A | 0.4 |
---|---|
Reading 1 (no. of paperclips) | |
Reading 2 (no. of paperclips) | |
Average (no. of paperclips) |
Current in A | 0.5 |
---|---|
Reading 1 (no. of paperclips) | |
Reading 2 (no. of paperclips) | |
Average (no. of paperclips) |
Current in A | 0.6 |
---|---|
Reading 1 (no. of paperclips) | |
Reading 2 (no. of paperclips) | |
Average (no. of paperclips) |
Graph
Conclusion
As the current increases the number of paper clips held also increases.
This means that the strength of the electromagnet increases with increasing current, which agrees with our prediction.
In fact, since the line of best fit is a straight line through the origin, we can be even more precise.
We can say that, the strength of the electromagnet is directly proportional to the current.
If you double the current, you double the strength of the electromagnet.